The Rydberg equation is

$\begin{align*}\frac{1}{\lambda} = R \left(\frac{1}{n_f^2} - \frac{1}{n_i^2} \right)\end{align*}$
The longest wavelength in the Lyman series will have $n_i = 2$ and the longest wavelength in theBalmer series will have $n_f = 3$ . The ratio of these wavelengths is
$\begin{align*}\frac{\lambda_L}{\lambda_B} = \frac{\displaystyle \left(\frac{1}{2^2} - \frac{1}{3^2} \right)}{\displaystyle \l...$
Therefore, answer (A) is the correct one.

Solution to 1996 Problem 9